Case 1: C B > 10 -6 M; [OH-] = N*C B ; pOH = - log([OH- ]; pH = 14.00 – pOH
Exam 2
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2. Strong base.
exam 2
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Case 1: C HA > 10-6 M; [H+ ] = C HA; pH = -log(C HA).
Exam 2 Topic
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X. Systematic Treatment of Aqueous Equilibria.
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