8 Matching Annotations
  1. Nov 2025
    1. Figure 19.5.3: he Standard Hydrogen Electrode. The SHE consists of platinum wire that is connected to a Pt surface in contact with an aqueous solution containing 1 M H+ in equilibrium with H2 gas at a pressure of 1 atm. Note, the SHE can act as either an Anode or Cathode.

      Note that Pt is absent from the full redox rxn and the resulting half rxn. Don't accidentally get confused Pt is just the surface the redox rxn is occurring on (its interion differentiates its status as not being apart of the "reactants" or "productions").

    1. The moment current flows [Zn+2] increases while the [Cu+2] decreases and this can be seen by the images in part (b) of figure 19.2.3 as the Zinc anode dissolves and copper ions attach themselves to the electrode and become reduced to neutral copper.

      The moment current flows [Zn+2] increases while the [Cu+2] decreases and this can be seen by the images in part (b) of figure 19.2.3 as the Zinc anode dissolves and copper ions attach themselves to the electrode and become reduced to neutral copper.

    2. he moment current flows [Zn+2] increases while the [Cu+2] decreases and this can be seen by the images in part (b) of figure 19.2.3 as the Zinc anode dissolves and copper ions attach themselves to the electrode and become reduced to neutral copper.

      Not sure if this is clear to all but in the case it is not the resulting image on the right (b) shows the anode, or Zn, thinning down as ions enter the solution. The reason for the "fuzziness" or "spikeyness" on the Cu cathode is due to the formation of Copper crystals from electrons in solution.

    1. Note: E is not energy but electric potential. (19.1.7)W=q⋅Δ⁢E

      The reasoning behind this is because it represents the amount of energy per given unit charge (In this case Coulombs, but Joule / Volt could work too). A great analogy I saw online because this topic can be confusing for intro to electrochemistry is the height analogy. That is an object on a high ledge does not have any kinetic energy but rather potential energy (the unit here being per g or lb that increases with increased potential energy).

  2. Oct 2025
    1. Note, like any logarithm, you can write this in the log form, on in the power form (17.2.15)[A−][H⁡A]=10p⁢H−p⁢K⁢A

      Notice that the way the equation solves that with the solved value. If 10^pH-pKA is greater than 1, the Conjugate Base or [A-] is in higher concentration than the lewis acid [HA], alternatively an increased HA concentration means a larger denominator --> 10^pH-pKA closer to 0; Conjugate Acid is higher in concentration.

    2. Mix a weak acid (or base) with a soluble salt of its conjugate.

      In order to obtain a buffer, the complete neutralization of either the acid or the base must be avoided. Thus weak acids are used (and my guess no strong bases as well) because the complete dissociation of its ions would prevent the suspension of the pH.

    1. and we can calculate pOH for a weak acid

      This formula is similar to the pH formula of a weak acid given its H+ concentration. This likely means due to the logarithmic nature that a hypothetical titration curve could be plotted with similarly its H+ concentration to that of its OH- concentration (logarithmic relationship).

    2. So we can define the percent ionization of a weak acid as (16.3.36)%I=[A−][H⁡A]i⁢(100)

      This formula will tell you the amount of A- Ions in solution, note that this formula is for a monoprotic weak acid (less it also applies to di+)?