776 Matching Annotations
  1. Oct 2026
    1. A number cube is rolled. Find the probability of rolling an odd number.

      For the sake of the example, you should list what the possibilities are and note that three of them are odd numbers. You should show that n(S) is 6 and n(E) is 3, then show the P(E) math that n(E)/n(S)=3/6.

    1. These patterns lead us to the Binomial Theorem, which can be used to expand any binomial. (x+y)n=∑k=0n(nk)⁢xn−k⁢yk=xn+(n1)⁢xn−1⁢y+(n2)⁢xn−2⁢y2+...+(nn−1)⁢x⁢yn−1+yn

      Introduce the term expanded form here.

    1. deposits

      r=1+(.06/12)=1.005 n=(10 years)(12 mo/yr)=120 a1=200

      S_120=(200(1-1.005^120))/(1-1.005) =(200(1-1.81939))/(-.005) =(200(-0.81939))/(-.005) =(-163.879346)/(-.005) =32,775.86936

    2. Exercise 11.4.2⁢C

      Shouldn't this have been an example to examine? Is n=n? I don't know what's going on with this problem. Is it formatting? It looks like this is supposed to be from k=1 to n=10 for a_n=5-6k.

    1. The recursive formula for a geometric sequence with common ratio r and first term a1

      We just did two problems like this, but none using the previous definition of ar, ar^2, ar^3, ...

    2. Many jobs offer an annual cost-of-living increase to keep salaries consistent with inflation. Suppose, for example, a recent college graduate finds a position as a sales manager earning an annual salary of $⁢26,000

      I like how you're describing the situations that pertain to the study of sequence and series. It makes it more tangible.

    1. without rotating axes.

      This was shown earlier with comparisons of A and C in the general equation having like or unlike signs for B=0. Opposite signs are a hyperbola, like signs are an ellipse as long as A is not equal to C and B=0.

      It's unnecessary to rotate the axes to determine the conic sections, so I'm not sure about your statement.

    2. following

      According to the section on generalized equation identification, a positive A and C value are an ellipse. It's worth saying somewhere in here that these cases are for B not equal to 0.

    3. in the new coordinate plane. It may be represented in terms of its coordinate axes. u→=x′⁢i′+y′⁢j′=x′⁢(i⁢cos⁡θ+j⁢sin⁡θ)+y′⁢(−i⁢sin⁡θ+j⁢cos⁡θ)Substitute.=i⁢x′⁢cos⁡θ+j⁢x′⁢sin⁡θ−i⁢y′⁢sin⁡θ+j⁢y′⁢cos⁡θDistribute.=i⁢x′⁢cos⁡θ−i⁢y′⁢sin⁡θ+j⁢x′⁢sin⁡θ+j⁢y′⁢cos⁡θApply commutative property.=(x′⁢cos⁡θ−y′⁢sin⁡θ)⁢i+(x′⁢sin⁡θ+y′⁢cos⁡θ)⁢jFactor by grouping.

      i cos theta + j sin theta is new notation. are i and j vectors or scalar? Am I supposed to recognize i and j = to something specific? Why are you saying that x'i'+y'j'=xi+yj? This section needs a LOT more explanation and maybe some more graphs.

    4. ). We may write the new unit vectors in terms of the original ones. (10.4.3)i^′=cos⁡θ⁢i^+sin⁡θ⁢j^

      This, and the previous graph, need some examples.

      We should have covered the axes translation in the introductory section on i and j coordinate systems and defined the unit vector there.

    5. on the new rotated plane (Figure 10.4.4

      This needs more trigonometry and graphs to explain it. I really don't understand the cos theta projecting from the y' axis to the x axis.

      Is r=1? cos(theta)=x/r, x=rcos(theta)

      Are we defining the sin and cos from x' and y' or x and y, or both?

    1. form

      Why did I bother learning parabolas as y=ax^2? Learning it in this format isn't more helpful. Why not just state that we learned y=ax^2 and that a=4p?

    2. If we sketch lines tangent to the parabola at the endpoints of the latus rectum, these lines intersect on the axis of symmetry

      I'm trying to figure out why this information is useful.

    1. What is the standard form equation of the ellipse that has vertices (−3,3)

      This would be better served as an example. There is only one example for ellipses!

    2. for any point on the ellipse. We will begin the derivation by applying the distance formula. The rest of the derivation is algebraic. d1+d2=2⁢a(x−(−c))2+(y−0)2+(x−c)2+(y−0)2=2⁢aDistance formula(x+c)2+y2+(x−c)2+y2=2⁢aSimplify expressions.(x+c)2+y2=2⁢a−(x−c)2+y2Move radical to opposite side.(x+c)2+y2=[2⁢a−(x−c)2+y2]2Square both sides.x2+2⁢c⁢x+c2+y2=4⁢a2−4⁢a⁢(x−c)2+y2+(x−c)2+y2Expand the squares.x2+2⁢c⁢x+c2+y2=4⁢a2−4⁢a⁢(x−c)2+y2+x2−2⁢c⁢x+c2+y2Expand remaining squares.2⁢c⁢x=4⁢a2−4⁢a⁢(x−c)2+y2−2⁢c⁢xCombine like terms.4⁢c⁢x−4⁢a2=−4⁢a⁢(x−c)2+y2Isolate the radical.c⁢x−a2=−a⁢(x−c)2+y2Divide by 4.[c⁢x−a2]2=a2⁢[(x−c)2+y2]2Square both sides.c2⁢x2−2⁢a2⁢c⁢x+a4=a2⁢(x2−2⁢c⁢x+c2+y2)Expand the squares.c2⁢x2−2⁢a2⁢c⁢x+a4=a2⁢x2−2⁢a2⁢c⁢x+a2⁢c2+a2⁢y2Distribute a2a2⁢x2−c2⁢x2+a2⁢y2=a4−a2⁢c2Rewrite.x2⁢(a2−c2)+a2⁢y2=a2⁢(a2−c2)Factor common terms.x2⁢b2+a2⁢y2=a2⁢b2Set b2=a2−c2x2⁢b2a2⁢b2+a2⁢y2a2⁢b2=a2⁢b2a2⁢b2Divide both sides by a2⁢b2x2a2+y2b2=1Simplify

      A derivation and explanation of b^2=a^2-c^2 is appropriate here too. The reasoning is not just algebraic, but geometric also, and based off of the distance formulas and right triangle created from b to O, c to O and distance a=d1=d2.

    1. If we are solving for x, the x column is replaced with the constant column. If we are solving for y, the y column is replaced with the constant column

      This is a great observation that I didn't notice.

    1. , let’s multiply the two matrices together to see if the product equals the identity, if A⁢A−1=I

      display problems for AA-1 third row matrix and A-1A 1st row, second matrix

    2. Use the formula to find the multiplicative inverse of A=[1−22−3]

      You told me to use the formula, but then solved it without using the formula. You didn't even explain where it came from.

    1. Write the system of equations in row-echelon form. x−2⁢y+3⁢z=9−x+3⁢y=−42⁢x−5⁢y+5⁢z=17

      My row-echelon matrix looks a little different, which is worth mentioning, but still find that the answer is (1,-1,2). I don't understand why your R1 shows fractions when the original set for R1 should be 1, -2, 3, 9 according to the first equation. BTW, I've never seen any solution sets in here for x, y, and z expressed in parenthesis.

    2. Any leading 1 is below and to the right of a previous leading 1. Any column containing a leading 1 has zeros in all other positions in the column.

      rows 2 and 3 in the shown row-echelon form has numbers other than zero

    3. We can also write a matrix containing just the coefficients. This is called the coefficient matrix. [344−2]

      This text often introduces information as if it was new even though we've been working on it. It's irritating.

    1. m×n indicating m rows and n columns. Matrix entries are defined first by row and then by column. For example, to locate the entry in matrix A identified as ai⁢j,we look for the entry in row i,column j.

      Why are we calling rows both m and i, and columns both n and j?

    1. repeated linear factor occurringn n times

      I'm not seeing it in the generalized equation expansion of P(x)/Q(x). This is just repeated information from the previous section on non-repeated linear factors.

    2. In other words, it is a return from the single simplified rational expression to the original expressions, called the partial fractions.

      Partial fractions are composed to form a single rational expression.

    1. Just as with a parabola and a line, there are three possible outcomes when solving a system of equations representing a circle and a line.

      again, a statement about how the solutions for a single outcome and no solution will present themselves if we're not going to examine examples and do exercises on them.

    2. Intersection of a Parabola and a Line

      You need a statement in here about how the single solution and non solution will present themselves upon examination.

    1. The process of elimination will result in a false statement,

      Examining how these inconsistent systems present themselves is necessary. It helps with recognition.

    2. the primary tool we will be using is called Gaussian elimination, named after the prolific German mathematician Karl Friedrich Gauss

      I would like to see more sections structured this way.

      Bold print for "Gaussian elimination"

    1. Given the cost function C⁡(x)=0.85⁢x+35,000

      Things to cover here, C(x) and R(x) are represented by the y-axis, that's why they are annotated as y_1 and y_2. x represents the number of units (the x-axis). For the R(x)=px, there's no information on where this number would come from. If we're going to call P(x) the profit function, shouldn't we use an inequality?

    2. The shaded region to the right of the break-even point represents quantities for which the company makes a profit. The shaded region to the left represents quantities for which the company suffers a loss. The profit function is the revenue function minus the cost function, written as P⁡(x)=R⁡(x)−C⁡(x)

      Just to complete the graph and put forth the educational information, the area to the left of the break-even point is called loss.

    1. formula

      This should be annotated as v_1 and v_2, not u and v.

      There is no clear reason why v/|v|=<5/sqrt(29)+2/sqrt(29)> and u/|u|=<3/sqrt(58)+7sqrt(58)> ? Should the plus signs be commas? Is there some mysterious vector u I'm not seeing here?

    2. Find the dot product of v1=5⁢i+2⁢j

      I just want to enter a note that it was not obvious that vector-v=<a,b> and <a,b> is equal to a i-vector+b j-vector.

    3. Example 8.8.5

      Not sure how you got here given the problem the example gave. 17+16=31?? This problem description doesn't even belong here. Shouldn't it be "given u= and v=, find 3u+2v="?

    1. How to: Given a pair of parametric equations, sketch a graph by plotting points

      This has been covered, although not formally. This should have been done back at it's introduction.

    1. Eliminate the parameter from the given pair of parametric equations and write as a Cartesian equation: x⁡(t)=2⁢cos⁡t

      none of these rotated clockwise.

    2. Eliminate the parameter and write as a rectangular equation. x⁡(t)=t2y⁡(t)=ln⁡t, t>0

      Are you saying that Cartesian equations are not rectangular equations? Shouldn't we give credit where credit is due? Why is this in bold print with no definition?

      y=1/2(ln(x))

    3. as a function of x

      So, even though the instructions at the beginning of the section would have me find t=5-y and substitute into x(t) as x(5-y), it is actually going to be easier to find y(t) since the quadratic equation produced by y^2 isn't two binomials. This should be an example, not an exercise.

    4. An object travels at a steady rate along a straight path (−5,3)

      So, normally m is calculated as the difference in y divided by the difference in x, which is -1/2. You're saying that since we're parameterizing, we have to find m_x dependent on t (=2) and m_y dependent on t (=-1). So the actual slope m is -1/2, it's just (m_y)/(m_x).

      And then we're using the x-value and y-value of the first coordinate as the b value, which I don't understand. Just how does that play out mathematically? Are we just using the first value of (=5,3) for the b values of x(t) and y(t)? This is so unclear. Is it the first coordinate because we're adding time to it?

    1. is a complex number, then (8.5.12)zn=rn⁢[cos⁡(n⁢θ)+i⁢sin⁡(n⁢θ)](8.5.13)zn=rn c⁢i⁢s⁡(n⁢θ)

      cis is not an identity and is not useful. De Moive did not have cis in his theorem so why is it here?

    2. , then the product of these numbers is given as: (8.5.8)z1⁢z2=r1⁢r2⁢[cos⁡(θ1+θ2)+i⁢sin⁡(θ1+θ2)](8.5.9)z1⁢z2=r1⁢r2 c⁢i⁢s⁢(θ1+θ2)

      cis is not an identity and is never useful.

    3. . We then find cos⁡θ=xr

      Not sure why I can't use cos(theta)=x instead of x/r seeing as how the equation is multiplied by the radius and will cancel it out.

    4. Find the rectangular form of the complex number given r=13

      Not sure why you calculated r, it was given in the problem. And although the 122 is wrong, the answer is right.

    5. Thus, the solution is 4⁢2 c⁢i⁢s⁡(3⁢π4)

      This notation is not an identity. Please stop. I find it preposterous that we use a cartesian coordinate system for imaginary numbers at all. 3+4i could well be (3,4i), but the point (5,6) would only be 5x+6y, which has never been taught. There's a lot here that isn't being discussed.

    6. . It measures the distance from the origin to a point in the plane. For example, the graph of z=2+4⁢i

      Fill in your own math! I don't see ANYTHING about the complex conjugate in here! I don't see anything about z^2-=(x+iy)(x-iy) making |z|=sqrt(x^2+y^2)