number cube
dice
number cube
dice
A number cube is rolled. Find the probability of rolling an odd number.
For the sake of the example, you should list what the possibilities are and note that three of them are odd numbers. You should show that n(S) is 6 and n(E) is 3, then show the P(E) math that n(E)/n(S)=3/6.
number cube
A dice?
pp
!
These patterns lead us to the Binomial Theorem, which can be used to expand any binomial. (x+y)n=∑k=0n(nk)xn−kyk=xn+(n1)xn−1y+(n2)xn−2y2+...+(nn−1)xyn−1+yn
Introduce the term expanded form here.
To determine the expansion on (x+y)5
Just curious under what circumstances this is useful, really?
Find each binomial coefficient
(11,4)=330
Key Equations
Derivations for these should have been included.
rr
Notation!
cancel out the (n−r) items that we do not wish to line up.
This is unclear. Is there a derivation we can do for this?
example
What?? Where did you get 15 from? Why did it stop at 4? I don't see how we could have used the Multiplication Principle.
e said earlier is equal to
Maybe? But when?
club
A club of people? You mean 6 people in a club?
nn
?
How many ways can the family line up for the portrait if the parents are required to stand on each end?
Is this 2!x3! or 2X3!?
We can add the number of vegetarian options to the number of meat options to find the total number of entrée options.
no picture, just a description.
infinite
S_infinity
deposits
r=1+(.06/12)=1.005 n=(10 years)(12 mo/yr)=120 a1=200
S_120=(200(1-1.005^120))/(1-1.005) =(200(1-1.81939))/(-.005) =(200(-0.81939))/(-.005) =(-163.879346)/(-.005) =32,775.86936
nn
?
nn
?
nn
what's with this notation?
Exercise
This is not geometric as written
approaches 1
Shouldn't this say (1-r^n)?
e sum of a geometric series is defined when −1<r<1.
Exercise 11.4.6A is not defined, but says it's defined.
Exercise
I find r=3/2 which is greater than 1, so doesn't it diverge? That would mean that because r is not between -1 and 1 the sum is not defined?
series increases without bound
so the series does not converge, and therefore diverges and is undefined.
Infinite Geometric Series
Why are we not doing this for an Arithmetic Series?
geometric
b) has a formatting problem with k not showing as an exponent.
Exercise 11.4.2C
Shouldn't this have been an example to examine? Is n=n? I don't know what's going on with this problem. Is it formatting? It looks like this is supposed to be from k=1 to n=10 for a_n=5-6k.
interest earned.
Glad to see we'll be determining the results to this problem at the end of the chapter, unlike the previous two.
ch as the truck’s value.
Are we neve going to do this problem then?
it often makes sense to use an initial term of a0 instea
Maybe you could describe that situation??
and a vertical intercept of −8
missing graph
term must be given.
a(n-1)?
recursive formula for the arithmetic sequence.
Ok, why the bold print?
Writing
I see that a5=a4+2, which makes sense, but I would have liked to see the actual derivation.
Arithmetic
Isn't this supposed to be "arithmatic"?
salary grows by a constant factor.
Are we not doing this problem then?
hits
Not sure where 1.026a^n came from, shouldn't this be 2.6^n? The answer would then be approximately 34,812.
formula
Derivations are preferred over formulas. This is math, after all.
sequence
Good to know to keep the negative signs.
and
This 2 shouldn't be here.
sequence can be written in terms of the initial term and the common ratio r.
Doesn't this statement belong after the derivation for r?
Given a geometric sequence with a1=3
This should have been the first topic.
explicit formulas
This was the introductory sequence we didn't use in an example! Frustrating organization!
The recursive formula for a geometric sequence with common ratio r and first term a1
We just did two problems like this, but none using the previous definition of ar, ar^2, ar^3, ...
is the common ratio, the sequence will be (11.3.1){a1,a1r,a1r2,a1r3,...}.
since we're using a_2=ra_1, a_3=ra_2, etc, why not introduce that here?
result
a4 should be negative
Many jobs offer an annual cost-of-living increase to keep salaries consistent with inflation. Suppose, for example, a recent college graduate finds a position as a sales manager earning an annual salary of $26,000
I like how you're describing the situations that pertain to the study of sequence and series. It makes it more tangible.
formula
Should the last two terms in the sequence be 5/2 and 17/6?
sequence
This is the wrong answer. How exactly do you come up with the right answer for this one? Even the sequence finders online can't find this.
sequence
Yeah, the comma conglomerate at the end is hard to decipher.
The first five terms are {−2,2,−32,1,−58}
-3/2, -5/8
nn
? notation
graph
Wrong graph
nn
?
formula
[5pt] ?
rectangular
Shouldn't the answer be written in terms of Ax^2+Bxy+Cy^2...?
Because sinθ is in the denominator,
Where's the logic that follows to this statement?
without rotating axes.
This was shown earlier with comparisons of A and C in the general equation having like or unlike signs for B=0. Opposite signs are a hyperbola, like signs are an ellipse as long as A is not equal to C and B=0.
It's unnecessary to rotate the axes to determine the conic sections, so I'm not sure about your statement.
following
According to the section on generalized equation identification, a positive A and C value are an ellipse. It's worth saying somewhere in here that these cases are for B not equal to 0.
HOWTO: USING THE DISCRIMINANT TO IDENTIFY A CONIC
...when B is not equal to zero
. For example, the degenerate case of a circle or an ellipse is a point: (10.4.2)Ax2+By2=0,
A and C?
. We will use half-angle identities.
This should have been mentioned the first time.
Rewrite the 13x2−63xy+7y2=16
Some indicators that I'm on the right path would be nice, like sin theta and cos theta, what x' and y' =.
Next, we find sinθ
Where did these equations come from?
term
Why the comma?
in the new coordinate plane. It may be represented in terms of its coordinate axes. u→=x′i′+y′j′=x′(icosθ+jsinθ)+y′(−isinθ+jcosθ)Substitute.=ix′cosθ+jx′sinθ−iy′sinθ+jy′cosθDistribute.=ix′cosθ−iy′sinθ+jx′sinθ+jy′cosθApply commutative property.=(x′cosθ−y′sinθ)i+(x′sinθ+y′cosθ)jFactor by grouping.
i cos theta + j sin theta is new notation. are i and j vectors or scalar? Am I supposed to recognize i and j = to something specific? Why are you saying that x'i'+y'j'=xi+yj? This section needs a LOT more explanation and maybe some more graphs.
, we have representations of x
I can't make the jump, you need to explain this. u is in terms of x' and y', not x and y.
Why is u=x'i'+y'j'=xi+yj?
). We may write the new unit vectors in terms of the original ones. (10.4.3)i^′=cosθi^+sinθj^
This, and the previous graph, need some examples.
We should have covered the axes translation in the introductory section on i and j coordinate systems and defined the unit vector there.
on the new rotated plane (Figure 10.4.4
This needs more trigonometry and graphs to explain it. I really don't understand the cos theta projecting from the y' axis to the x axis.
Is r=1? cos(theta)=x/r, x=rcos(theta)
Are we defining the sin and cos from x' and y' or x and y, or both?
vectors
This is the first time you've used the hat notation
rotated
Why not mention that the -1 in front of the xy term is related to the slope of the axis.
when A and B have opposite signs.
so, are you saying it's actually: -Ax^2+By^2=0 and Ax^2-By^2=0?
degenerate conic
This should be a bold print with definition
origin
Why are the absolute values in the graph coordinates, but not the equations?
form
Why did I bother learning parabolas as y=ax^2? Learning it in this format isn't more helpful. Why not just state that we learned y=ax^2 and that a=4p?
parabolas
I think parabola b, facing left, is supposed to have the y-axis to the right of the directix.
If we sketch lines tangent to the parabola at the endpoints of the latus rectum, these lines intersect on the axis of symmetry
I'm trying to figure out why this information is useful.
latus rectum.
This is the first time that I've heard of a latus rectum.
vertex
The vertex of y^2=4px at (0,0) is not on the axis.
the coordinates of the vertices are \((\pm a,0)\0
?
Graphing Hyperbolas Centered at the Origin
This should have been placed before the (h,k) section.
equation
Shouldn't x be subtracted from y?
located
+-9
derivation
Please include the derivation for b^2=c^2-a^2
hyperbola
The light cascading on the wall of a house from a lamp forms a hyperbola.
a portion of a conic
It looks like a parabola?
shock wave
I take issue with the figure. Shock waves are spherical, not circular.
How to: Given the standard form of an equation for an ellipse centered at (h,k)
Isn't this the same instructions you've printed over and over?
If the equation is in the form x2b2+y2a2=1
division signs are missing.
Graphing Ellipses Centered at the Origin
I would've put this section following the section that had h,k centered at the origin.
What is the standard form equation of the ellipse that has vertices (−3,3)
This would be better served as an example. There is only one example for ellipses!
for any point on the ellipse. We will begin the derivation by applying the distance formula. The rest of the derivation is algebraic. d1+d2=2a(x−(−c))2+(y−0)2+(x−c)2+(y−0)2=2aDistance formula(x+c)2+y2+(x−c)2+y2=2aSimplify expressions.(x+c)2+y2=2a−(x−c)2+y2Move radical to opposite side.(x+c)2+y2=[2a−(x−c)2+y2]2Square both sides.x2+2cx+c2+y2=4a2−4a(x−c)2+y2+(x−c)2+y2Expand the squares.x2+2cx+c2+y2=4a2−4a(x−c)2+y2+x2−2cx+c2+y2Expand remaining squares.2cx=4a2−4a(x−c)2+y2−2cxCombine like terms.4cx−4a2=−4a(x−c)2+y2Isolate the radical.cx−a2=−a(x−c)2+y2Divide by 4.[cx−a2]2=a2[(x−c)2+y2]2Square both sides.c2x2−2a2cx+a4=a2(x2−2cx+c2+y2)Expand the squares.c2x2−2a2cx+a4=a2x2−2a2cx+a2c2+a2y2Distribute a2a2x2−c2x2+a2y2=a4−a2c2Rewrite.x2(a2−c2)+a2y2=a2(a2−c2)Factor common terms.x2b2+a2y2=a2b2Set b2=a2−c2x2b2a2b2+a2y2a2b2=a2b2a2b2Divide both sides by a2b2x2a2+y2b2=1Simplify
A derivation and explanation of b^2=a^2-c^2 is appropriate here too. The reasoning is not just algebraic, but geometric also, and based off of the distance formulas and right triangle created from b to O, c to O and distance a=d1=d2.
respectively
should be (0, +-c)
: (a) Horizontal ellipse with center (0,0)
Only one graph shown, does not depict either description. Is actually figure 10.1.14.
pper triangular form,
First mention of this.
Equation
-6x should be -6z
If we are solving for x, the x column is replaced with the constant column. If we are solving for y, the y column is replaced with the constant column
This is a great observation that I didn't notice.
Multiply row 2 by −3
Much easier to read as -3R2+R1=R1
. Using the formula to calculate the inverse of a 2
The first use of the formula should have been already covered. This section is very unorganized.
Find the inverse of the 3×3
Not sure what I did wrong, a solution set would be great.
, let’s multiply the two matrices together to see if the product equals the identity, if AA−1=I
display problems for AA-1 third row matrix and A-1A 1st row, second matrix
Use the formula to find the multiplicative inverse of A=[1−22−3]
You told me to use the formula, but then solved it without using the formula. You didn't even explain where it came from.
formula
You didn't do any examples with the A-1 formula.
Multiply row 2 by−1. −1. [103−101−52]
?
then find the produc
?
and the identity matric is equal to the product of the identity matrix and A
Second equation should be presented as IA
of
%
annual interest
The annual interest in only one year?
interest
%
paying
%
Evaluate
Erroneous nesting of equation structures.
Solve the system using matrices. x+4y−z=42x+5y+8z=15x+3y−3z=1
How is that the answer?? 2x+5y+8z is not equal to 1 for (1,1,1)
solution
first time I've seen (x, y, z).
Write the system of equations in row-echelon form. x−2y+3z=9−x+3y=−42x−5y+5z=17
My row-echelon matrix looks a little different, which is worth mentioning, but still find that the answer is (1,-1,2). I don't understand why your R1 shows fractions when the original set for R1 should be 1, -2, 3, 9 according to the first equation. BTW, I've never seen any solution sets in here for x, y, and z expressed in parenthesis.
Row-echelon form [1ab01d001]
I learned this in high school. Why is it in preCalculus?
Any leading 1 is below and to the right of a previous leading 1. Any column containing a leading 1 has zeros in all other positions in the column.
rows 2 and 3 in the shown row-echelon form has numbers other than zero
When the columns represent the variables x
missing answer: "Erroneous nesting of equation structures"
We can also write a matrix containing just the coefficients. This is called the coefficient matrix. [344−2]
This text often introduces information as if it was new even though we've been working on it. It's irritating.
equipment
15%?
m×n indicating m rows and n columns. Matrix entries are defined first by row and then by column. For example, to locate the entry in matrix A identified as aij,we look for the entry in row i,column j.
Why are we calling rows both m and i, and columns both n and j?
Equation
[
a
Bb_1x in the first partial fraction breakdown has a large 1 and a small x...formatting
repeated linear factor occurringn n times
I'm not seeing it in the generalized equation expansion of P(x)/Q(x). This is just repeated information from the previous section on non-repeated linear factors.
In other words, it is a return from the single simplified rational expression to the original expressions, called the partial fractions.
Partial fractions are composed to form a single rational expression.
bounded
should I be defining a feasible region here?
graph is drawn with a dashed line.
I don't know where I may have learned this.
graph a nonlinear inequality
shouldn't this have been presented in the inequality system.
system
Both of these were ellipses in parabolas without considering that any of the four solutions could be invalid yielding one or no solutions.
Solve
interesting to note that this system has one solution and the line is therefore tangent to the circle.
substitution
It didn't say to graph, but I believe there should always be a picture with the story.
Just as with a parabola and a line, there are three possible outcomes when solving a system of equations representing a circle and a line.
again, a statement about how the solutions for a single outcome and no solution will present themselves if we're not going to examine examples and do exercises on them.
Intersection of a Parabola and a Line
You need a statement in here about how the single solution and non solution will present themselves upon examination.
Figure 9.2.5
Missing figure!
Analysis
Examination
The process of elimination will result in a false statement,
Examining how these inconsistent systems present themselves is necessary. It helps with recognition.
possible
I like the geographic representation.
the primary tool we will be using is called Gaussian elimination, named after the prolific German mathematician Karl Friedrich Gauss
I would like to see more sections structured this way.
Bold print for "Gaussian elimination"
three-by-three systems
bold print?
ordered triple
bold print?
a bit more organization and
Organization should be taught in every problem we examine.
: Finding the Break-Even Point and the Profit Function Using Substitution
This should probably be after the circus ticket and meal ticket problems.
Clearly
If we're just going to examine the profit of the profit-loss function, shouldn't this be an inequality? Is P(x) a parameterization?
that the profit function has a negative value until x=50,000
profit-loss function
Given the cost function C(x)=0.85x+35,000
Things to cover here, C(x) and R(x) are represented by the y-axis, that's why they are annotated as y_1 and y_2. x represents the number of units (the x-axis). For the R(x)=px, there's no information on where this number would come from. If we're going to call P(x) the profit function, shouldn't we use an inequality?
The shaded region to the right of the break-even point represents quantities for which the company makes a profit. The shaded region to the left represents quantities for which the company suffers a loss. The profit function is the revenue function minus the cost function, written as P(x)=R(x)−C(x)
Just to complete the graph and put forth the educational information, the area to the left of the break-even point is called loss.
first
11/2=5.5
Figure
Shouldn't the coordinates be in <> notation?
formula
This should be annotated as v_1 and v_2, not u and v.
There is no clear reason why v/|v|=<5/sqrt(29)+2/sqrt(29)> and u/|u|=<3/sqrt(58)+7sqrt(58)> ? Should the plus signs be commas? Is there some mysterious vector u I'm not seeing here?
Figure
shouldn't these have the <> notation in the graph?
Find the dot product of v1=5i+2j
I just want to enter a note that it was not obvious that vector-v=<a,b> and <a,b> is equal to a i-vector+b j-vector.
The dot product of two vectors v=⟨a,b⟩
What does this number mean? What does it represent? What is it measuring? What is it's use?
travels
are we saying that it's time-dependent? Is it parametric?
and a direction angle θ
sin theta should have a division sign in there
general form of the vector.
First time with this term.
vectors
so are the vector notations supposed to be above the i and j in the v-vector linear combination? It's unclear.
written
shouldn't it be y_2-y_1?
of
This equation is new. Maybe introduce it first since there is no arrow?
vector
the arrows are really helpful. The bold letters are not showing up.
First find the standard position. v=⟨7−3,4−2⟩=⟨4,2⟩
This is the first time I've heard it called a standard position vector.
Figure
Shouldn't the vector terminal point be labeled <2,3>?
have
should say v1
Example 8.8.5
Not sure how you got here given the problem the example gave. 17+16=31?? This problem description doesn't even belong here. Shouldn't it be "given u= and v=, find 3u+2v="?
vector
missing a v with the 1/2
drawn
grammar
have
u should be on the next line
magnitude
should be 6 root 2
Figure
Missing graph
rectangular
Cartesian
How to: Given a pair of parametric equations, sketch a graph by plotting points
This has been covered, although not formally. This should have been done back at it's introduction.
Rectangular
Cartesian
Rewriting this set of parametric equations is a matter of substituting x
Shouldn't we be annotating the removal of the parameter by indicating y(x)=?
Eliminate the parameter from the given pair of parametric equations and write as a Cartesian equation: x(t)=2cost
none of these rotated clockwise.
trigonometric equations
Why is this in bold print with no definition?
Eliminate the parameter and write as a rectangular equation. x(t)=t2y(t)=lnt, t>0
Are you saying that Cartesian equations are not rectangular equations? Shouldn't we give credit where credit is due? Why is this in bold print with no definition?
y=1/2(ln(x))
Figure
no graph
Figure 8.6.8
missing graph
as a function of x
So, even though the instructions at the beginning of the section would have me find t=5-y and substitute into x(t) as x(5-y), it is actually going to be easier to find y(t) since the quadratic equation produced by y^2 isn't two binomials. This should be an example, not an exercise.
). In this example, we limited values of t
So we are finding coordinates x(t) and y(t) for f(t). This is a lot like drawing circles and ellipses.
An object travels at a steady rate along a straight path (−5,3)
So, normally m is calculated as the difference in y divided by the difference in x, which is -1/2. You're saying that since we're parameterizing, we have to find m_x dependent on t (=2) and m_y dependent on t (=-1). So the actual slope m is -1/2, it's just (m_y)/(m_x).
And then we're using the x-value and y-value of the first coordinate as the b value, which I don't understand. Just how does that play out mathematically? Are we just using the first value of (=5,3) for the b values of x(t) and y(t)? This is so unclear. Is it the first coordinate because we're adding time to it?
in the t column
t column showing named as \(t)
Construct a table of values and plot the parametric equations: x(t)=t−3
This should have started with an example.
is a number on an interval, I
Why the comma?
is a complex number, then (8.5.12)zn=rn[cos(nθ)+isin(nθ)](8.5.13)zn=rn cis(nθ)
cis is not an identity and is not useful. De Moive did not have cis in his theorem so why is it here?
, then the quotient of these numbers is (8.5.10)z1z2=r1r2[cos(θ1−θ2)+isin(θ1−θ2)], z2≠0
cis is not an identity
, then the product of these numbers is given as: (8.5.8)z1z2=r1r2[cos(θ1+θ2)+isin(θ1+θ2)](8.5.9)z1z2=r1r2 cis(θ1+θ2)
cis is not an identity and is never useful.
. We then find cosθ=xr
Not sure why I can't use cos(theta)=x instead of x/r seeing as how the equation is multiplied by the radius and will cancel it out.
Find the rectangular form of the complex number given r=13
Not sure why you calculated r, it was given in the problem. And although the 122 is wrong, the answer is right.
in polar form.
Ok, so 2 cos (pi/6) is a number, why aren't we writing it that way?
Thus, the solution is 42 cis(3π4)
This notation is not an identity. Please stop. I find it preposterous that we use a cartesian coordinate system for imaginary numbers at all. 3+4i could well be (3,4i), but the point (5,6) would only be 5x+6y, which has never been taught. There's a lot here that isn't being discussed.
in polar form.
I'm not using this cis notation. You can't use it to solve anything since it's a mixture of sin and cos and isn't an identity.
abbreviation
cis? Never heard of it before.
Figure
there's a |z| with no value in the graph.
formula
I'm not supposed to be learning formulas in math. I'm supposed to be learning derivation and modeling.
. It measures the distance from the origin to a point in the plane. For example, the graph of z=2+4i
Fill in your own math! I don't see ANYTHING about the complex conjugate in here! I don't see anything about z^2-=(x+iy)(x-iy) making |z|=sqrt(x^2+y^2)
nd 1<ab<2. All fo
Should be: 1<a/b<2
Figure
missing graphs
Figure
missing graphs
8.4: Polar Coordinates - Graphs
This whole section would be better if you included math with the +-(pi)(k)