3 Matching Annotations
  1. Last 7 days
    1. Although the electrons cancel and the metal atoms are balanced, the total charge on the left side of Equation 6.2.7 (+4) does not equal the charge on the right side (+8). Because the reaction is carried out in the presence of aqueous acid, we can add H⁡A+ as necessary to either side of the equation to balance the charge. By the same token, if the reaction were carried out in the presence of aqueous base, we could balance the charge by adding OHA− as necessary to either side of the equation to balance the charges.

      Another topic that I found difficult is to balance the charges for redox reactions. It is clear to me that electrons should cancel out and the atoms should balance out too; however, I find it difficult to know how many ions, either H⁺ or OH⁻, are needed to be added so that the charges are balanced on both sides.

    1. idation state is a useful tool for keeping track of electron transfers. It is most commonly used in dealing with metals and especially with transition metals. Unlike metals from the first two columns of the periodic table, such as sodium or magnesium, transition metals can often transfer different numbers of electrons, leading to different metal ions (e.g., sodium is generally found as NaA+ and magnesium is almost always MgA2+, but manganese could be MnA2+, MnA3+, and so on, as far as MnA7+). Oxidation state is a number assigned to an element in a compound according to some rules. This number enables us to describe oxidation-reduction reactions, and balancing redox chemical reactions. When a covalent bond forms between two atoms with different electronegativities the shared electrons in the bond lie closer to the more electronegative atom:

      One topic I found difficult to grasp was oxidation states in transition metals and why some of them could exist in more than one oxidation state. Oxidation states are important in recording the transfer of electrons; however, I have not been able to comprehend how it is possible to know which oxidation state a particular transition metal exists in a compound.

  2. Oct 2026
    1. Thus enthalpy is not the only factor that determines whether a process is spontaneous. For example, after a cube of sugar has dissolved in a glass of water so that the sucrose molecules are uniformly dispersed in a dilute solution, they never spontaneously come back together in solution to form a sugar cube. Moreover, the molecules of a gas remain evenly distributed throughout the entire volume of a glass bulb and never spontaneously assemble in only one portion of the available volume. To help explain why these phenomena proceed spontaneously in only one direction requires an additional state function called entropy (S), a thermodynamic property of all substances that is proportional to their degree of "disorder". In Chapter 13, we introduced the concept of entropy in relation to solution formation. Here we further explore the nature of this state function and define it mathematically.

      What is the significance of entropy in predicting the spontaneity of reactions, and why doesn't dissolved sugar spontaneously revert to its sugar cube state?