Although the electrons cancel and the metal atoms are balanced, the total charge on the left side of Equation 6.2.7 (+4) does not equal the charge on the right side (+8). Because the reaction is carried out in the presence of aqueous acid, we can add HA+ as necessary to either side of the equation to balance the charge. By the same token, if the reaction were carried out in the presence of aqueous base, we could balance the charge by adding OHA− as necessary to either side of the equation to balance the charges.
Another topic that I found difficult is to balance the charges for redox reactions. It is clear to me that electrons should cancel out and the atoms should balance out too; however, I find it difficult to know how many ions, either H⁺ or OH⁻, are needed to be added so that the charges are balanced on both sides.