23 Matching Annotations
  1. Mar 2023
    1. Thus the maximum capacity augmenting path has residual capacity atleast (v* - v)/m. Now consider a sequence of 2m consecutive maximum capacityaugmentations starting with the flow x. If each of these augmentations augments atleast (v* - v)/2m units of flow, then within 2m or fewer iterations we will establisha maximum flow.

      Why is this \(2m\) what the fuck dude.

      Ok, check: here for more information.

    2. This argument shows that within 2m consecutive iterations, thealgorithm either establishes a maximum flow or reduces the residual capacity of themaximum capacity augmenting path by a factor of at least 2.

      This is an unstated claim where, the proof comes before this paragraph.

    3. 7.2

      Undergraduate based, algorithm.

      Show your residual Δ network after each augmentation. Verify you have the maximum flow by exhibiting an appropriate cut.

      Why is there a double arc for the graph 7.21(b)? Is it a lower bound for the flow on the network?

    4. An augmentation on arc (i, j) might, however,create an additional arc (j, i) with rji > 0 and therefore also create an additionalinequality d(j) ~ d(i) + 1 that the distanceJabels must satisfy.

      This is just using the inductive hypothesis. The indecutive hypothesis hold for all the neighbours of the curren node \(i\), after the delection of the arcs, the neigboring vertices decreased, therefore, valid distance label condition still holds.

    5. Lemma 7.5

      The shortest augmenting path matains a correct distance label for all the vertices during the iterations. By valid, we mean that there exists some way such that \(d(j) = d(i) + 1\), where \((i, j)\in A\), for all \(i\in N\).

  2. Feb 2023

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