1,682 Matching Annotations
  1. Mar 2020
    1. The need to use an infinitesimally small piece of mass dm suggests that we can write the moment of inertia by evaluating an integral over infinitesimal masses

      Session 21 intro

    1. Since →rr→\mathbf{\overset{\to }{r}} is constant

      not sure this is correct, but magnitude \(r\) is constant in uniform circular motion The real reason that \(\frac{d\vec{r}}{dt}=0\) is that in uniform circular motion, the position vector \(\vec{r}\) only changes in the \(\hat{\theta}\) or \(-\hat{\theta}\) direction, which are parallel or antiparallel to \(\vec{\theta}\). The cross product of parallel or antiparallel vectors is zero!

    1. the summation becomes an integral:

      Use this integral and its associated example to tackle the problem of the one meter rod, using linear mass densities \(\lambda_{iron}=8.0\frac{g}{cm}\) and \(\lambda_{al}=2.7\frac{g}{cm}\)

    2. Two particles of masses m1m1{m}_{1} and m2m2{m}_{2} separated by a horizontal distance D are let go from the same height h at different times

      brain burner!

    3. The radius of Earth is 6.37×106m6.37×106m6.37\times {10}^{6}\,\text{m}, so the center of mass of the Earth-moon system is (6.37 − 4.64) ×106m=1.73×106m=1730km×106m=1.73×106m=1730km×\,{10}^{6}\,\text{m}=1.73\times {10}^{6}\,\text{m}=1730\,\text{km} (roughly 1080 miles) below the surface of Earth.

      We discussed this

    4. This is Newton’s second law

      This is why an astronomer can focus on the trajectory of a star or planet or galaxy as if all of its mass is concentrated at a point located at the center of mass.

    1. Multiple objects can collide and stick together, forming a single object

      Like a set of boxcars in the freight yard hooking together and moving off at a new speed.

    1. but those changes are identical in magnitude, though opposite in sign.

      Newton's third law is best understood in this way. The "equal but opposite reaction" is encoded quantitatively by the changes of momentum, or exchanges of momenta.

    1. when a force is applied for an infinitesimal time interval dt, it causes an infinitesimal impulse d→JdJ→d\mathbf{\overset{\to }{J}},

      So, for instance, the moon exchanges momentum with Earth as it travels around its orbit, but second by second, we can compute the amount of impulse, e.g.,

      \(\vec{J}=\Delta \vec{p}=\int_{0.0\,s}^{1.0\,s} \left[ \frac{Gm_{\oplus}m_{moon}}{\left[r\left(t\right)\right]^2}\right]dt\)

    1. Finding the force from the potential energy is mathematically easier than finding the potential energy from the force, because differentiating a function is generally easier than integrating one.

      Good strategy note

    1. In Relativity, we will see that conservation of energy still applies to a non-classical particle, but for that to happen, we have to make a slight adjustment to the definition of energy.

      Correctamente! Slight adjustment, indeed, plus E becomes a component of the total relativistic momentum in four dimensions, \(\vec{p}=\left(p_x,\, p_y,\, p_z\right)\longrightarrow \vec{p}=\left(E,\, p_x,\, p_y,\, p_z\right) \).

  2. Feb 2020
    1. The string vibrates around an equilibrium position, and one oscillation is completed when the string starts from the initial position, travels to one of the extreme positions, then to the other extreme position, and returns to its initial position.

      Very good description of the periodic motion of a string on a guitar. The frequency of oscillation is in the audible range, e.g., A above middle C is 440 Hz.

    1. First consider the horizontal or x-axis:

      I can now see why a few of you, on HW 4, used this notation, \( F_{net\ x}=T_{2x} - T_{1x}=0\) rather than the way I usually write it, \(\sum F_x = T_{2x}-T_{1x}=0\).

    1. Join the ladybug in an exploration of rotational motion. Rotate the merry-go-round to change its angle or choose a constant angular velocity or angular acceleration. Explore how circular motion relates to the bug’s xy-position, velocity, and acceleration using vectors or graphs.

      Not sure why this paragraph is here.

    2. due to the force of the air on the wing

      "force of the air on the wing" ↔︎ Many scientists describe aerodynamic lift as the pressure differential \(\Delta p\) between the top and bottom of the wing, effecting every square inch of the wing.

  3. pressbooks.online.ucf.edu pressbooks.online.ucf.edu
    1. Often, an analytic solution is intractable or impossible, requiring lengthy numerical solutions or simulations to get approximate results.

      MANY scientific jobs require this skill, numerical solution of differential equations.

    1. This means a skydiver with a mass of 75 kg achieves a terminal velocity of about 350 km/h while traveling in a pike (head first) position, minimizing the area and his drag.

      about the same as a small 2" sphere

    1. but →ww→\mathbf{\overset{\to }{w}} has components along both axes,

      The free body diagram on the right is a bit different than the sketches I used in Session 12.<br> The author's \(\vec{w}_y\) vector is attached at its tail to the mass point, whereas in my sketch, it is slid over and attaches at the tip of \(\vec{w}\). But both are acceptable and useful. As I have mentioned several times, how you diagram forces etc. can be different from the author's and from my way of diagramming, and still be fine.

  4. pressbooks.online.ucf.edu pressbooks.online.ucf.edu
    1. without the necessity of physical contact between objects

      Or, once could redefine contact to mean an interaction "at a distance," as the author mentions here.

    2. A quantitative definition of force can be based on some standard force

      This is because force is a derived quantity, based on time, space and mass measurements.

    1. a

      It is not clear to me what this expression is supposed to be. Be careful when checking your answer for h. For example,

      $$\frac{24\frac{m}{s}}{9.8 \frac{m}{s^2}}=2.49\, s$$

    2. solid volcanic rocks

      also known as "bombs" "Accretionary lava ball comes to rest on the grass after rolling off the top of an ‘a‘a flow in Royal Gardens subdivision. Accretionary lava balls form as viscous lava is molded around a core of already solidified lava (photo by J.D. Griggs, 7/2/83, JG2562) (picture #012)."

  5. Jan 2020
    1. Projectile to satellite.

      Newton was the first one to work out this idea of projectile becoming a spacecraft in orbit, depending on initial conditions \(\left(x\left( 0\right),\, y\left( 0 \right)\right)\) and \(\vec{v}\left( 0 \right)\).

    2. two independent one-dimensional motions

      They are not really independent except mathematically. They are actually coupled. For instance, the horizontal range, \(x_{max}\), is controlled by the size of \(v_y\left(0\right)\)

    3. Vertical Motion

      In the fourth equation here,

      $$v_y^2=v^2_{0y}-2g\left(y-y_0\right),$$

      if you have eyes to see, you can see the remnants of potential energy and kinetic energy terms.

    4. very simple

      Note that the author uses a slightly different notation than I use:

      1. author, \(-g=-9.8\frac{m}{s^2}\)
      2. Dr. Brueckner, \(g=-9.8\frac{m}{s^2}\)

      Keep this in mind as you study.

    5. Let’s assume all forces except gravity (such as air resistance and friction, for example) are negligible

      standard assumption for basic physics like PHY2048

    1. derivative with respect to time →v(t),v→(t),\mathbf{\overset{\to }{v}}(t), we find

      We discussed this in session 7, concerning uniform circular motion. The direction of the acceleration vector \(\vec{a}\left( t\right)\) is the direction of the \(\Delta \vec{v}\left( t\right)\) vector.

    1. Analytical methods of vector addition are exact, contrary to graphical methods, which are approximate.

      I.e., draw the sketch then let the numbers do the talking

    2. In many physical situations, we often need to know the direction of a vector.

      Simply the vector itself, divided by the magnitude of the vector. $$\hat{u}=\frac{\vec{U}}{U}$$

    1. Analytical skills and problem-solving abilities can be applied to new situations whereas a list of facts cannot be made long enough to contain every possible circumstance.

      This is why we do not emphasize formula sheets and memorization.

    1. so it would take roughly 109/10−10=1019109/10−10=1019{10}^{9}\text{/}{10}^{-10}={10}^{19} hydrogen atoms to stretch across the diameter of the Sun.

      This is news to me, but accurate. Note that this number of hydrogen atoms is much smaller than \(1.00\, mole\). Curious

    2. study of physics makes other sciences easier to understand

      This is a polite way of saying, "All science is either physics or stamp collecting," which Prof. Ernest Rutherford said way back in his days of discovering the nuclear structure of matter. (Ernest Rutherford)

    3. What is most useful is knowing the basic laws of physics and developing skills in the analytical methods for applying them.

      This is how most scientists work:

      • from easily remembered basic principles and examples,
      • then extending to new concepts and previously unseen problems.

      (Enrico Fermi)

      This mental process will be helpful

      1. during our exams, which, by definition, will have previously unseen problems,
      2. during future courses deeper into your UCF curriculum, and
      3. throughout all of your professional work as a professional user of physics knowledge.

      ...helpful IF you want to excel. (Albert Einstein)

  6. Dec 2019
    1. all natural phenomena

      Professor Galileo wrote, "Philosophy is written in this grand book — I mean the universe — which stands continually open to our gaze, but it cannot be understood unless one first learns to comprehend the language and interpret the characters in which it it written. It is written in the language of mathematics, and its characters are triangles, circles and other geometrical figures, without which it is humanly impossible to understand a single word of it; without these, one is wandering about in a dark labyrinth.” [(Assayer, VI)]

      That is our challenge, the mountain we climb: to understand the grand book of nature.

      (https://bibdig.museogalileo.it/Teca/Viewer?an=300984&lang=en)

    1. The reflected rays seem to originate from behind the mirror, locating the virtual image.

      Good example of what makes an image virtual. I always describe it this way: if you place a photographic film at the image location (behind the mirror, in this case) and no light rays actually hit the film, which is true in this case, then it is a virtual image.

  7. Nov 2019
    1. This type of aberration is called a coma

      Here is a coma test panel, comparing stars imaged at the center of a Canon 24mm f/1.4L II lens, at intermediate distance and at the edge of the lens:

      At the edge, you get a lot more coma abberation, but at f2.8, it seems minimized.

    2. For example an achromatic doublet consisting of a converging lens made of crown glass and a diverging lens made of flint glass in contact can dramatically reduce chromatic aberration

      E,g., the Zeiss apochromat lens that focuses all colors nicely.

      "Achieving this level of correction is not simple. It requires the use of exceptional quality optical materials: long-crown glass (fluor crown glass and calcium fluoride) and special short flint glass."

    1. Eventually, if the Sun could shrink down to a diameter of about 6 kilometers, only light beams sent out perpendicular to the surface would escape. All others would fall back onto the star ([link]).

      Schwarzschild radius" of the Sun. We do not think it will ever get collapsed to this small of a size, because the Sun is not large enough to have a supernova detonation.

    2. If the speed you need to get away is faster than the fastest possible speed in the universe, then nothing, not even light, is able to escape.

      This is the classical way of thinking about black holes, and a century after Sir Isaac Newton wrote Principia, another scientist, John Michell, worked it out using non-relativity concepts.

    3. We want to know what speeds are required to escape from the gravitational pull of different objects.

      Escape velocity:

      1. from the surface of Earth, \(11,200\frac{m}{s}\)
      2. from event horizon of a black hole, \(c=3\times 10^8\frac{m}{s}\)
    1. object

      Diameter of DNA helix is about 2 nanometers. So wavelengths on the order of a nanometer are good to use. Rosalind Franklin probably used \(\lambda = 0.15\:nm\) for her xray diffraction images.

    2. However, when it interacts with smaller objects, it displays its wave characteristics prominently.

      E.g., our handheld diffraction gratings,

      with 500 lines per millimeter. That is about one line every 2000 nm, so just a few times larger than the typical Roy G. Biv wavelengths.

    1. But a more common arrangement is to use a third convex lens as an eyepiece, increasing the distance between the first two and inverting the image once again

      Second flip = nice!

    2. Telescopes gather far more light than the eye

      The best way to think of this idea is the concept of aperture: the pupil of your eye, a few millimeters, vs., e.g. the aperture of the Hubble Space Telescope (HST), about 2.4 meters. HST is about 300 times wider, about 90,000 times more area than the human eye's pupil.

      The HST is about the size of a school bus.

      (Hubble being transferred from the Vertical Assembly Test Area (VATA) to the High Bay at the Lockheed assembly plant in preparation for transport to the Kennedy Space Center (KSC) after final testing and verification.)

    1. The eyepiece forms a case 2 final image

      Notice that, in this diagram, the rays are almost parallel coming out of the eyepiece to the eyeball. If the rays are parallel, your eye does not have to strain to focus the image on your retina

    2. the eye is marvelous in its ability to see

      An understatement. When we view a star in the night sky, our retina collects very small numbers of Roy G. Biv photons per second.

    1. An ideal thin lens has two refracting surfaces but the lens is thin enough to assume that light rays bend only once.

      One refractive interaction, an approximation to the two physical interactions.

    1. 23.11 Reactance, Inductive and Capacitive

      Bypass or skim the diagrams. We talked about oscillating circuits from the standpoint of energy, but we did not get into any detail of this section, 23.11.

    1. 23.8 Electrical Safety: Systems and Devices

      Bypass. It won't be on Exam 3, although Florida residents would do well to read about the GFI technology, which many major appliances and pool pumps have.

    1. 8: (a) Using information in Figure 5, find the height of the instructor’s head above the water, noting that you will first have to calculate the angle of incidence. (b) Find the apparent depth of the diver’s head below water as seen by the instructor.

      Brain burner deluxe....

    2. 4: Will light change direction toward or away from the perpendicular when it goes from air to water? Water to glass? Glass to air?

      I like this question. You can work it out with typical values of indices of refraction, \(n_{air}=1.00,\, n_{water}=1.33,\, n_{glass}=1.5\)

    3. a lawn mower goes from grass to footpath.

      Here, the left wheels move more slowly on the thick grass, while the right wheels move more rapidly when they hit the sidewalk. Net result: lawn mower turns left, line of travel cuts away from the normal (dotted line).

    4. when a lawn mower goes from a footpath to grass

      Left wheels move more rapidly on the sidewalk, and right wheels move more slowly on the thick grass. Net result: lawn mower turns right, line of travel close to the normal (dotted line).

    1. PhET Explorations: Bending Light

      Very nice simulation of refraction. "More tools" can even produce total internal reflection. It is an HTML file. Download it then click it open -- runs good.

    1. Since the wavelength of light is less than a micron (a thousandth of a millimeter), it acts like a ray in the many common situations in which it encounters objects larger than a micron.

      Good rule of thumb.

    1. An AM radio transmitter broadcasts 50.0 kW of power uniformly in all directions. (a) Assuming all of the radio waves that strike the ground are completely absorbed, and that there is no absorption by the atmosphere or other objects, what is the intensity 30.0 km away? (Hint: Half the power will be spread over the area of a hemisphere.) (b) What is the maximum electric field strength at this distance?

      I also like this problem: will the electrons in the antenna circuit of the typical radio oscillate enough to an electric field of this intensity? Enough to provide an audible, uninterrupted signal without having to compete with too much random noise in the background? Because I have noticed, while driving around Orlando, that some of our Orlando AM radio stations really fade out in various locations, especially at night.

    2. Assume the helium-neon lasers commonly used in student physics laboratories have power outputs of 0.250 mW. (a) If such a laser beam is projected onto a circular spot 1.00 mm in diameter, what is its intensity? (b) Find the peak magnetic field strength. (c) Find the peak electric field strength.

      I like this calculation because lasers are frequently used to move electrons and ions around, with the E field. So knowing, for example, the size of the molecule or metallic lattice, you can tune the laser intensity to get the molecule or ion or electron to dance exactly the way you want it to dance.

    3. As before, a relatively strong electric field is accompanied by a relatively weak magnetic field in an electromagnetic wave, since , and is a large number

      Deceptive statement, in my opinion, because saying one field is weak is completely relative to the two scales we have for \(E\) and \(B\). For the electric field the author uses \(\frac{V}{m}\) but for the magnetic field, Teslas. Perhaps a different scale should be used for magnetic field?

      It would be interesting to work out a system of constants and so forth so that E and B have the same unit and in radiation are the same size.

    4. What is the intensity in ?

      This reminds me of something that astronomers calculate: the "solar constant,", which, it turns out is not quite constant because the Sun's output varies on a daily time scale and slowly over its 11-year sunspot cycle. Currently, the observed value is about \(1360.66\frac{W}{m^2}\).

    5. A wave’s energy is proportional to its amplitude squared ( or ).

      Oscillation, like the square \(x^2\) in a spring system and the "kinetic term" with a \(v^2\) in it

  8. Oct 2019
    1. PhET Explorations: Radio Waves and Electromagnetic Fields

      One of the best Interactive Simulations. I completely recommend it. Download the java file, then open it. Try the "radiated field" option -- it is spectacular.