1,682 Matching Annotations
  1. Oct 2019
    1. charges radiate whenever they are accelerated

      Stated as an aside, but this is a critical concept. The source of electromagnetic radiation is accelerating charge, like the northern lights

    2. For clarity, the waves are shown only along one direction, but they propagate out in other directions too.

      In fact, the intensities of radiation in each direction is controlled primarily by the shape and dimensions of the antenna.

    1. Show that, when SI units for and are entered, the units given by the right-hand side of the equation in the problem above are m/s.

      One-time exercise, to get over the strangeness of \(\epsilon_0\) and \(\mu_0\).

    2. When the values for and are entered into the equation for ,

      Now we can see where the mysterious constants, \(\epsilon_0\) and \(\mu_0\) come in and combine for the speed of light, $$c^2=\frac{1}{\mu_0 \epsilon_0}$$

    1. We therefore concentrate on the rate of change of current, , as the cause of induction.

      Significant: \(\mathcal{emf}\, \propto \, \frac{\Delta I}{\Delta t}\) is going to lead to oscillation

    1. (a) When this bar magnet is thrust into

      The coil gains RIGHTWARD field lines, do the coil's induced current produces leftward field lines, \(\vec{B}_{coil}\)

      Images (b) and (c) show induced fields \(\vec{B}_{coil}\) consistent with Lenz' Law.

    1. product of the area and the component of the magnetic field perpendicular to it.

      If we were to make a full general definition, accounting for shapes of circuit and of the field, then there'd be

      • a ton of trig, and
      • a ton of calculus
    1. If a star is moving toward or away from us, its lines will be in a slightly different place in the spectrum from where they would be in a star at rest

      "Complicating factor," yes, but this Doppler shifting is something we understand, and it gives us basic leverage to extract more information:

      1. "blue shift" meaning a λ wavelength shift to shorter than normal λ, and you can extract the speed at which the object approaches the observer;
      2. "red shift" in which the observed λ wavelength is shifted to a longer λ, plus you can extract the speed at which the object is moving away from the observer.

      Here is an interesting diagram of Doppler shift information uncovering currents underneath sunspots!:

    2. increased wavelength and decreased frequency

      Because the speed of light c is a constant, and because the electromagnetic wave equation is c = λf,

      • when the wavelength increases (redshift), the frequency decreases, but
      • when the wavelength decreases (blueshift), the frequency has to get bigger.
    3. Observer C sees the waves stretched out by the motion and sees a redshift

      The arrow of Observer C's wavelength is slightly off, too short. It should go from the top edge of the dark red circle to the top edge of the next circle in (reddish pink).

    1. one of Einstein’s motivations was to solve difficulties in knowing how different observers see magnetic and electric fields.

      As I always say, "What does the observer see?"

    1. The torque reverses once the loop rotates past θ = 0.

      Would be a restoring force, leading to oscillation, if current continues in the initial direction.

    2. When current is passed through the loops, the magnetic field exerts torque on the loops, which rotates a shaft.

      We will try this demonstration in Friday's session 23.

    1. The magnetic field exerts a force on a current-carrying wire in a direction given by the right hand rule

      We viewed this force effect in Session 21, with the big horseshoe magnet and the thick copper strip between the poles of the magnet.

    1. The properties of charged particles in magnetic fields are related to such different things as the Aurora Australis or Aurora Borealis and particle accelerators.

      For Exam 2, we will bypass the aurora and other examples past this point.

    1. RHR-1 states that, to determine the direction of the magnetic force on a positive moving charge, you point the thumb of the right hand in the direction of , the fingers in the direction of , and a perpendicular to the palm points in the direction of .

      I severely hate this version of the right hand rule. However, other semingly normal people might like it, so I will include it in the textbook without mass crossouts.

    2. relatively simple

      "relatively simple" ← nice, but do not forget the appearance/disappearance of the magnetic field depending on the motion of the observer.

    1. Magnetic field lines are continuous, forming closed loops

      Always true, unlike electric field lines. There are electric monopoles, e.g., proton and electron, with porcupine and anti-porcupine field lines. There are looped \(\vec{E}\) field lines starting with a dipole array.

    2. The direction of the magnetic field is tangent to the field line at any point in space. A small compass will point in the direction of the field line.

      Good -- similar to our idea about electric field lines.

    1. crudely

      crude indeed. As far as we can tell, electrons have no structure, so saying that it spins on an axis like a planet is very crude. We make do, saying that the electron has intrinsic spin angular momentum, \(\plusmn \frac{\hbar}{2}\)

    2. they can also be magnetized

      Any large structure built of steel, like a building of steel girders or a warship, can be magnetized by pounding the steel: pile drivers, riveters, etc. Liberty ship, keel plates

    3. Ferromagnets

      This topic should follow "Electromagnets" because we understood electromagnets a century earlier than we savvied ferromagnetism (iron atoms as tiny electromagnets).

    1. All electric motors, with uses as diverse as powering refrigerators, starting cars, and moving elevators, contain magnets. Generators, whether producing hydroelectric power or running bicycle lights, use magnetic fields.

      We can thank Michael Faraday for these developments.

    1. the time constant for an circuit

      The circuit's "time constant" \(\tau = RC\) is related to the half-life of the circuit. Both terms are used by scientists in exponentially growing or decaying systems.

    1. Power is energy per unit time (watts)

      So after an amount of time \(\Delta t\), all of the energy of a battery will dissipate at the circuit element, e.g., the light bulb, where stored Joules from the battery are dissipated as light and heat. At that point, the bulb goes cold.

    2. the loss of electrical power, called a voltage drop,

      NO! NO! NO! Voltage is measured in \(\frac{Joule}{Coulomb}\) but power is different, \(\frac{Joule}{second}\)!!

    1. electromotive force, abbreviated emf

      This term traces way back to the 1800s, before we had figured out everything and unified the electromagnetic theory. So calling it a force is anachronistic, but we still use it for the sake of custom. The common symbol is an upper case script E, \(\mathcal{E}\)

  2. Sep 2019
    1. He was thinking about momentum! In the momentum view, the skateboarders’ values actually are equal in magnitude, though their vectors have opposite directions, positive for rightward, negative for leftward.

      This was as far as the reading went to prepare for Exam 1. The sections after this will be on Exam 2!

    1. A power transmission line is hung from metal towers with glass insulators having a resistance of . What current flows through the insulator if the voltage is 200 kV? (Some high-voltage lines are DC.)

      We will work out this exercise in Session 13, if possible

    2. Such a linear relationship doesn’t always occur.

      For instance, in the solar corona, positive ions, protons and electrons are flying around in "current sheets" blazing through the corona, and we have a hard time figuring out the Ohmic resistance for such complicated currents. YouTube

  3. pressbooks.online.ucf.edu pressbooks.online.ucf.edu
    1. Repeat the above example on Example 3, but for a wire made of silver and given there is one free electron per silver atom.

      Will work this out in Session 13

    2. The batteries of a submerged non-nuclear submarine supply 1000 A at full speed ahead. How long does it take to move Avogadro’s number () of electrons at this rate?

      Good problem to try out.

    3. (a) A defibrillator sends a 6.00-A current through the chest of a patient by applying a 10,000-V potential as in the figure below. What is the resistance of the path? (b) The defibrillator paddles make contact with the patient through a conducting gel that greatly reduces the path resistance. Discuss the difficulties that would ensue if a larger voltage were used to produce the same current through the patient, but with the path having perhaps 50 times the resistance. (Hint: The current must be about the same, so a higher voltage would imply greater power. Use this equation for power: .)

      This problem is slightly out of place... might be better in a later section of Ch. 20

    4. Negative charges move in the direction opposite to the electric field.

      We can do all of our calculations etc. with conventional current \(I\left(t\right)\), but when actually trying to understand what is physically moving so that you can capture it or track it, you have to think about electrons, if you are in a regular circuit. Electrons require "reverse psychology."

    1. In open heart surgery, a much smaller amount of energy will defibrillate the heart. (a) What voltage is applied to the capacitor of a heart defibrillator that stores 40.0 J of energy? (b) Find the amount of stored charge.

      basic

    2. Energy Stored in Capacitors

      This formula, \(E=\frac{1}{2}\frac{1}{C}Q^2\) is actually related to oscillating currents in a circuit, as we shall see in Ch. 23.

    1. Suppose you want a capacitor bank with a total capacitance of 0.750 F and you possess numerous 1.50 mF capacitors. What is the smallest number you could hook together to achieve your goal, and how would you connect them?

      A brain burner.... work this out before Monday lecture if you can!!!!!!

    2. Find the total capacitance of the combination of capacitors

      First two capacitors are parallels: \(10\mu F\) and \(2.5\mu F\), so they simply add up the preliminary combo capacitance: \(C_{12}=12.5\mu F\). Easy.

      However, there is one cap in series with those first two, so now you employ the reciprocals formula for the total equivalent capacitance \(C_{eq}\), viz.

      $$\frac{1}{C_{eq}}=\frac{1}{C_{12}}+\frac{1}{0.30\mu F}$$

      So the common denominator is semi-nasty, \(cd=\left(12.5\right) \left(0.3\right) \longrightarrow 3.75 \)

      The rest is fractions. Don't forget to flip your \(\frac{1}{C_{eq}}\) fraction to get \(C_{eq}\) itself.

    3. More complicated connections of capacitors can sometimes be combinations of series and parallel

      We will get into this kind of brain burner on Monday, plus in a lab this coming week.

    4. for any number of capacitors connected in series.

      For \(n\) capacitors in series, $$\frac{1}{C_{eq}}=\frac{1}{C_1}+\frac{1}{C_2}+\cdots+\frac{1}{C_n}$$

    5. total voltage is the sum of the individual voltages

      ...or in Dr. Brueckner's parlance...

      $$\Delta V=\frac{Q}{C_{eq}}=\frac{Q}{C_1}+\frac{Q}{C_2}+\frac{Q}{C_3}$$

    6. voltages across the individual capacitors are
      • First capacitor, \(\Delta V_1=\frac{Q}{C_1}\)
      • Second capacitor, \(\Delta V_2=\frac{Q}{C_2}\)
      • Third capacitor, \(\Delta V_3=\frac{Q}{C_3}\)

      Note that the assumed charge load at the top of the first capacitor and at the bottom of the third capacitor are assumed to be the same size, \(\pm Q\). This is an application of the conservation of charge: the number of electrons stolen from the top plate is the same as the load of surplus electrons pushed into the bottom plate.

    1. permittivity

      This property, permittivity, is related to a substance's ability to be polarized. You can look up the specs for permittivity for many substances, e.g., for muscle fiber. However, the vacuum also takes a value, denoted \(\epsilon_0\) and used here for parallel plates, even though the vacuum has no substance.

    2. Since the field lines end on charges in the dielectric, there are fewer of them going from one side of the capacitor to the other.

      I detest this description, but it sort of makes some sense.

    3. store

      They also store energy in the electric field. This is the first time we have had something other than a Sir Isaac Newton \(F=ma\) style object with mass that can carry energy.

    1. No wonder it took astronomers a long time before they could measure such tiny shifts.

      The ancient Greeks could not measure with this precision, nor could the great Tycho Brahe. Kepler and Galileo, Newton and Halley: nope. But by the 1800s, yup, it started becoming possible, with better telescopes and measuring devices.

    2. In this text, we will use light-years as our unit of distance, but many astronomers still use parsecs when they write technical papers or talk with each other at meetings. To convert between the two distance units, just bear in mind: 1 parsec = 3.26 light-year, and 1 light-year = 0.31 parsec.

      This is the end of the material in Ch. 19 needed for Exam 1.

    3. Back in the days when most of our distances came from parallax measurements, a parsec was a useful unit of distance, but it is not as intuitive as the light-year.

      True, but astronomers still use both pc and LY!

    4. Bessel made the first authenticated measurement of the distance to a star (61 Cygni) in 1838, a feat that had eluded many dedicated astronomers

      Actually, a successful parallax measurement would've satisfied Plato, Aristotle et al., in their day, that Earth orbited the Sun. Unfortunately, they did not have good enough technology. But neither did Kepler and Galileo. Bessel bagged 61 Cygni 200+ years after Galileo.

    1. Explain in your own words why equipotential lines and surfaces must be perpendicular to electric field lines.

      I like this question. It is not a calculation, but it would be very nice to ask in class.........hmmmmm

    2. The equipotential lines around the heart, the thoracic region, and the axis of the heart are useful ways of monitoring the structure and functions of the heart.

      Very interesting

    3. the equipotential lines can be drawn simply by making them perpendicular to the electric field lines.

      A nice sketching exercise, equipotential lines of a dipole field. We might go through this in our first session after Exam 1.

    4. Because a conductor is an equipotential, it can replace any equipotential surface. For example, in Figure 1 a charged spherical conductor can replace the point charge, and the electric field and potential surfaces outside of it will be unchanged, confirming the contention that a spherical charge distribution is equivalent to a point charge at its center.

      Huge amount of difficult calculus behind this paragraph, enough to choke Sir Isaac Newton's horse.

    5. There can be no voltage difference across the surface of a conductor, or charges will flow.

      Correct. In a conducting material, the surplus charges will redistribute themselves into dynamic equilibrium, equal distances from each other.

    6. Equipotential Lines

      Visual way of thinking about the electromagnetic field, and very useful in quantum mechanics.

      Does this diagram remind you of a hydrogen atom/Quantum_Mechanics/09._The_Hydrogen_Atom/Bohr's_Hydrogen_Atom)?

    1. The potential at infinity is chosen to be zero.

      Just as we have the freedom to choose the elevation at which \(GPE=0.0\: J\) in a free fall problem near the surface of Earth: gym floor for a basketball problem, foot of a cliff for a Ferrari driving off a cliff problem, or the top of the same cliff for the Ferrari problem.

      NASA will take \(GPE=0.0\: J \text{ as } r \longrightarrow \infty \) since they are ranging way past the surface of Earth and out into space.

    2. it can be shown that

      One of the most annoying phrases in a physics textbook, "it can be shown that..." It is an author's evasive maneuver to avoid pages and pages of nasty calculus equations. Fortunately, that is okay in PHY2054!

    3. spherical charge distributions (like on a metal sphere) create external electric fields exactly like a point charge.

      Like the top of a Van de Graaff generator

    1. Electron Gun

      Yeah, the old timey method for generating a tv picuture, in the old tv tubes you used to see before flat screen technology took over. and The gun is in back, targeted at the front tv screen.

    2. field creates enough ionization

      I.e., ripping outer electrons from \(O_2\), \(N_2\) and \(H_2 O\) molecules, making them into conduction electrons. BANG!

    3. since points create greater fields than smooth surfaces.

      smooth versus sharp surfaces... Notice that insulators on telephone poles are nicely rounded ceramic or glass: and here is a closeup:

    4. E = V/d.

      To encode directionality, should be $$\vec{E}=-\frac{V}{d}$$\ or better yet, $$\vec{E}=-\frac{\Delta V}{\Delta s}$$

      ...but the authors are only talking about magnitudes here.

    5. since the path is parallel to the field,

      ...for this parallel plates example only. In general, one could have any kind of parabolic path between the plates, just as between elevations \(y=0.00\: m\) and \(y=40.0\: m\) from the top of the UCF library to the sidewalk, you could have any number of differing parabolic trajectories for a water balloon, depending on how hard you throw it and in what direction.

    6. The electric field strength between two parallel conducting plates separated by 4.00 cm is . (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be at zero volts. What is the potential 1.00 cm from that plate (and 3.00 cm from the other)

      This is another nice exercise.

    7. What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of

      Good. I like this basic problem

    1. move 5000 C of charge

      What does it mean for a battery to "move 5000 Coulombs"? A battery is rated in Amp hours, e.g.,

      An amp hour is a unit of charge: $$1.00\:A \times 1.00\:hour$$ $$1.00 \text{Coulomb}/\text{sec} \times 3600\:sec$$ $$3600 Coulombs$$

    2. PE can be found at any point by taking one point as a reference and calculating the work

      Similar to the customary approach to GPE in a free fall system. You can define any elevation you like to be the zero point of the potential energy function, $U$... $$U\left(y\right)=-mg\Delta y$$

    3. the potential energy (because it depends only on position)

      A scalar-valued function of position, though a ton of trig is usually encoded in the function

    4. as if the charge is going down an electrical hill

      Emphasis on "as if" !!! ...because of the ambiguity in forces and potential energies that rises from having positive and negative charges

    5. Electric Potential

      Further abstraction. \( \Delta V=-E \Delta x \) in a uniform field \(E\), e.g., between parallel charged plates. Does that formula remind you of the work formula?

    1. A motorcycle battery, for example, is small and would not be very successful in replacing the much larger car battery, yet each has the same voltage.

      Each has the same voltage -- determined by the cource charge array, not the apparatus (motorcycle vs. car)

    1. A certain five cent coin contains 5.00 g of nickel. What fraction of the nickel atoms’ electrons, removed and placed 1.00 m above it, would support the weight of this coin? The atomic mass of nickel is 58.7, and each nickel atom contains 28 electrons and 28 protons.

      OH MY GOODNESS!

    2. A test charge of is placed halfway between a charge of and another of separated by 10 cm. (a) What is the magnitude of the force on the test charge? (b) What is the direction of this force (away from or toward the charge)?

      We worked on similar calculations in class.

    3. f two equal charges each of 1 C each are separated in air by a distance of 1 km, what is the magnitude of the force acting between them? You will see that even at a distance as large as 1 km, the repulsive force is substantial because 1 C is a very significant amount of charge.

      Fairly easy to calculate, if you know the value of Coulomb's constant, \(k\)

    4. How far apart must two point charges of 75.0 nC (typical of static electricity) be to have a force of 1.00 N between them?

      I like this one, a good basic workout.

    5. distance between two objects squared to an accuracy of 1 part in .

      Theoretically, an inverse r<sup>2</sup> force has infinite range. So: gravitation and electromagnetism.

      Caveat: electromagnetic interactions can be screened, like losing your cell phone signal inside certain buildings on campus.

    1. How many electrons does it have?

      Nice exercise, relating the metric unit of charge, the Coulomb, to the fundamental charge,

      e=1.602 x 10<sup>-19</sup> Coulomb

      Hint: if its net charge is negative, then it has EXTRA electrons.

    2. A 50.0 g ball of copper has a net charge of . What fraction of the copper’s electrons has been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)

      A brain burner!

    3. When a glass rod is rubbed with silk, it becomes positive and the silk becomes negative—yet both attract dust. Does the dust have a third type of charge that is attracted to both positive and negative? Explain.

      I like this question.

    4. attraction of water to the charged rod

      I like this exercise. It is a cool demonstration you can do at home!

      1. Turn on the water to the lowest setting at which water streams out without forming droplets;
      2. charge up a plastic comb by scuffling it on your shirt;
      3. ease the comb in close to the vertical stream of water...

      ...How do you explain the fact that the stream dips slightly toward the comb (as in the photo) and never away from the comb?

    5. The same effect

      The electrons at the left hand side of the grey conducting block flee the copper colored rod, which is net negative. Those fugitive electrons head over to the right hand side of the conducting block. POLARIZED!

      This is basically what happened with the soda pop can demonstration.

    6. the leaves

      positive charges "move" to the sharpest topography of the device, just as they move to a students hair when touching the Van de Graaff generator.

    1. The mutual repulsion of excess positive charges on a spherical conductor distributes them uniformly on its surface. The resulting electric field is perpendicular to the surface and zero inside. Outside the conductor, the field is identical to that of a point charge at the center equal to the excess charge.

      Yes, important when applied to wires in a circuit.